A 12,Ω resistor and a 0.21, H inductor are connected in series to an ac source operating

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7.Alternating Current

easy

A $12\,\Omega $ resistor and a $0.21\, H$ inductor are connected in series to an $ac$ source operating at $20 \,volts$, $50\,cycle/second$. The phase angle between the current and the source voltage is.....$^o$

A

$30$

B

$40$

C

$80$

D

$90$

Solution

(c) $\tan \phi = \frac{{\omega L}}{R} = \frac{{2\pi \times 50 \times 0.21}}{{12}} = 5.5\, \Rightarrow \,\phi = {80^o}$

Standard 12

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