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4-1.Newton's Laws of Motion
easy
A $500 \,kg$ car takes a round turn of radius $50 \,m$ with a velocity of $36 \,km/hr$. The centripetal force is .......... $N$
A$250$
B$750$
C$1000$
D$1200$
(AIPMT-1999)
Solution
(c)$v = 36\frac{{km}}{h} = 10\frac{m}{s}$
$F = \frac{{m{v^2}}}{r} = \frac{{500 \times 100}}{{50}} = 1000\,N.$
$F = \frac{{m{v^2}}}{r} = \frac{{500 \times 100}}{{50}} = 1000\,N.$
Standard 11
Physics
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