A 500, kg crane takes a turn of radius 50 ,m with velocity of 36 ,km/hr. centripetal force is .

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4-1.Newton's Laws of Motion

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A $500\, kg$ crane takes a turn of radius $50 \,m$ with velocity of $36 \,km/hr.$ The centripetal force is ......... $N$

A$1200$

B$1000$

C$750$

D$250$

Solution

(b)$F = \frac{{m{v^2}}}{r} = \frac{{500 \times 100}}{{50}} = {10^3}\,N$

Standard 11

Physics

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