A bag contains, 7 different Black balls .and | vedclass

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Question

$\boxed{\frac{{{\,^{11}}{C_6} 	imes 7 	imes 6 	imes 5 	imes 4 	imes 3 	imes 2 	imes 10 	imes 9 	imes 8 	imes 7 	imes 6}}{{17 	imes 16 	im

Vedclass · Accepted Answer

$\frac{{^7{C_6}{\,^{10}}{C_5}}}{{^{17}{C_{11}}}} - \frac{{^1{C_1}}}{{^6{C_1}}}$

Vedclass · Answer

$\boxed{\frac{{{\,^{11}}{C_6} 	imes 7 	imes 6 	imes 5 	imes 4 	imes 3 	imes 2 	imes 10 	imes 9 	imes 8 	imes 7 	imes 6}}{{17 	imes 16 	imes 15 	imes 14 	imes 12 	imes 11 	imes 10 	imes 9 	imes 8 	imes 7}}} 	imes \boxed{\frac{1}{6}}$

                                                                              $ \Downarrow $                                                                                                                                                    $ \Downarrow $

(Prob. of $6$ black and $5$ red in frist $11$ draw)                                                                       Prob. of $7$ black ball in ${12^{th}}$ draw

$ = \frac{{{\,^7}{C_6} 	imes {\,^{10}}{C_5}}}{{{\,^{17}}{C_{11}}}} 	imes \frac{{{\,^1}{C_1}}}{{{\,^6}{C_1}}}$

A bag contains, $7$ different Black balls .and $10$ different Red balls, if one by one ball are randomely drawn untill all black balls are not drawn, then probability that this process is completed in $12 ^{th}$ draw, is equal to

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