A bag contains $4$ white and $3$ red balls. Two draws of one ball each are made without replacement. Then the probability that both the balls are red is

  • A

    $\frac{1}{7}$

  • B

    $\frac{2}{7}$

  • C

    $\frac{3}{7}$

  • D

    $\frac{4}{7}$

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