A ball of mass $2\,m$ is moving with velocity $v$ on a smooth surface collides elastically headon with another ball of mass $m$. If ball of mass $m$ reaches upto top of frictionless elevated plane, then velocity $v$ of heavy ball must be
$\sqrt {\frac{3}{2}\,gh} \,$
$\sqrt {\frac{{2gh}}{3}} $
$\sqrt {\frac{{8gh}}{9}} $
$\sqrt {\frac{{9gh}}{8}} $
Six identical balls are lined in a straight groove made on a horizontal frictionless surface. Two similar balls each moving with a velocity $v$ collide elastically with the row of $6\, balls$ from left. What will happen ?
A ball of mass $m$ strikes the inclined face of the wedge normally with speed $v_0$. The wedge is at rest on a rough horizontal surface before collision. The conservation of momentum is applicable for the event of collision for
$(i)$ $m$ as system, along $Y'$
$(ii) $ $M$ as system, along $Y'$
$(iii)$ $(M + m)$ as system, along $X$
$(iv)$ $(M + m)$ as system, along $Y$
Which of the following is correct?
A block of mass $m$ is moving with a velocity $u$ on a smooth horizontal surface towards a wedge of same mass initially kept at rest. Wedge is free to move in any direction. Initially the block moves up the smooth incline plane of the wedge to a height $h$ and again moves down back to the horizontal plane. In this process the wedge gains a velocity equal to
In the figure shown, the two identical balls of mass $M$ and radius $R$ each, are placed in contact with each other on the frictionless horizontal surface. The third ball of mass $M$ and radius $R/2$, is coming down vertically and has a velocity $= v_0$ when it simultaneously hits the two balls and itself comes to rest. Then, each of the two bigger balls will move after collision with a speed equal to
A ball of mass $m$ moving with speed $u$ collides with a smooth horizontal surface at angle $\theta$ with it as shown in figure. The magnitude of impulse imparted to surface by ball is [Coefficient of restitution of collision is $e$]