A ball of mass $'m'$ is released from the top of a smooth movable wedge of mass $'m'.$ When the ball collides with the floor,velocity of the wedge is $'v'.$ Then the maximum height attained by the ball after an elastic collision with the floor is :(Neglect any edge at the lower end of the wedge).

Two identical balls $A$ and $B$ having velocities of $0.5\, m s^{-1}$ and $-0.3 \, m s^{-1}$ respectively collide elastically in one dimension. The velocities of $B$ and $A$ after the collision respectively will be

$A$ bal $A$ collides elastically with another identical ball $B$ initially at rest $A$ is moving with velocity of $10m/ s$ at an angle of $60^o$ from the line joining their centres. Select correct alternative :

Three objects $A, B$ and $C$ are kept in a straight line on a frictionless horizontal surface. The masses of ${A}, {B}$ and ${C}$ are ${m}, 2\, {m}$ and $2\, {m}$ respectively. $A$ moves towards ${B}$ with a speed of $9$ ${m} / {s}$ and makes an elastic collision with it. Thereafter $B$ makes a completely inelastic collision with $C.$ All motions occur along same straight line. The final speed of $C$ is $....\,{m} / {s}$

As shown in the figure $a$ body of mass $m$ moving vertically with speed $3\, m/s$ hits a smooth fixed inclined plane and rebounds with a velocity $v_f$ in the horizontal direction. If $\angle$ of inclined is $30^o$, the velocity $v_f$ will be

A mass $'m'$ moves with a velocity $'v'$ and collides inelastically with another identical mass in rest. After collision the $I^{st}$ mass moves with velocity $\frac{v}{{\sqrt 3 }}$ in a direction perpendicular to the initial direction of motion. Find the speed of the $2^{nd}$ mass after collision