A ball of relative density 0.8 falls into water from a height of 2 m . depth to which ball will sink

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9-1.Fluid Mechanics

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A ball of relative density $0.8$ falls into water from a height of $2$ $m$. The depth to which the ball will sink is ........ $ m$ (neglect viscous forces) :

A

$8$

B

$2$

C

$6$

D

$4$

Solution

Buoyancy force $=(d v) g$

$m=d^{\prime} V$

acceleration$=\frac{\text {net force}}{m}=\frac{d V g}{d^{\prime} V}$

$\Rightarrow \frac{d \times g}{d^{\prime}}=\frac{10}{0.8}=12.5 \mathrm{m} / \mathrm{s}^{2}$

depth it gets sinked down$:$

$\Rightarrow(2 g \times 2)=0^{2}+2 \times g \times s$

$s=8 m$

Standard 11

Physics

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