A ball of relative density 0.8 falls into wat | vedclass

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Question

Buoyancy force $=(d v) g$

$m=d^{\prime} V$

acceleration$=\frac{	ext {net force}}{m}=\frac{d V g}{d^{\prime} V}$

$\Rightarrow \frac{d 	imes

Vedclass · Accepted Answer

$8$

Vedclass · Answer

Buoyancy force $=(d v) g$

$m=d^{\prime} V$

acceleration$=\frac{	ext {net force}}{m}=\frac{d V g}{d^{\prime} V}$

$\Rightarrow \frac{d 	imes g}{d^{\prime}}=\frac{10}{0.8}=12.5 \mathrm{m} / \mathrm{s}^{2}$

depth it gets sinked down$:$

$\Rightarrow(2 g 	imes 2)=0^{2}+2 	imes g 	imes s$

$s=8 m$

A ball of relative density $0.8$ falls into water from a height of $2$ $m$. The depth to which the ball will sink is ........ $ m$ (neglect viscous forces) :

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