2.Motion in Straight Line
medium

A balloon is rising vertically up with a velocity of $29 \,ms^{-1}$. A stone is dropped from it and it reaches the ground in $10$ seconds. The height of the balloon when the stone was dropped from it is...........$m$ ($g = 9.8\,m/{s^2}$)

A

$100$

B

$200$

C

$400$

D

$150$

Solution

(b) For stone to be dropped from rising balloon of velocity $29 \,m/s$.

$u = – \;29\;m/s,$ $t = 10 \,sec$.

$\therefore h = – \;29 \times 10 + \frac{1}{2} \times 9.8 \times 100$

$= -290 + 490 = 200 \,m$.

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.