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2.Motion in Straight Line
hard
A balloon rises, up with constant net acceleration of $10\,m / s ^2$. After $2\,s$ a particle drops from the balloon. After further $2\,s$ match the following columns. (Take $\left.g=10\,m / s ^2\right)$
| colum $I$ | colum $II$ |
| $(A)$ Height of particle from ground | $(p)$ $0$ |
| $(B)$ Speed of particle | $(q)$ $10$ SI unit |
| $(C)$ Displacement of particle | $(r)$ $40$ SI unit |
| $(D)$ Acceleration of particle | $(s)$ $20$ SI unit |
A
$( A \rightarrow r , B \rightarrow p , C \rightarrow s , D \rightarrow q )$
B
$( A \rightarrow q , B \rightarrow p , C \rightarrow s , D \rightarrow r )$
C
$( A \rightarrow r , B \rightarrow s , C \rightarrow p , D \rightarrow q )$
D
$( A \rightarrow q , B \rightarrow r , C \rightarrow s , D \rightarrow p )$
Solution
$(a)$
After $2\,s$, velocity of balloon and hence the velocity of the particle will be $20\,m / s (=a t)$ and its height from the ground will be $20\,m \left(=\frac{1}{2} a t^2\right)$ Now, $g$ will start acting on the particle.
Standard 11
Physics
