A batsman hits back a ball of mass 0.4 kg straight in direction of bowler without changing its initi

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4-1.Newton's Laws of Motion

easy

A batsman hits back a ball of mass $0.4 \; kg$ straight in the direction of the bowler without changing its initial speed of $15 \; ms ^{-1}$. The impulse imparted to the ball is $\dots \; Ns$

A

$12$

B

$22$

C

$32$

D

$42$

(JEE MAIN-2022)

Solution

Impulse $=$ change in momentum

$= m [ v -(- v )]=2 \; mv$

$=2 \times 0.4 \times 15=12 \; Ns$

Standard 11

Physics

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