A block C of mass m is moving with velocity v | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

Using conservation of linear momentum, we have

$m v_{0}=m v+2 m v$

$\Rightarrow v=\frac{v_{0}}{3}$

Using conservation of energy, we have

$

Vedclass · Accepted Answer

$\frac {2}{3} \frac {mv_0^2}{x_0^2}$

Vedclass · Answer

Using conservation of linear momentum, we have

$m v_{0}=m v+2 m v$

$\Rightarrow v=\frac{v_{0}}{3}$

Using conservation of energy, we have

$\frac{1}{2} m v_{0}^{2}=\frac{1}{2} k x_{0}^{2}+\frac{1}{2}(3 m) v^{2}$

where $x_{0}$ is compression in the string.

$	herefore m v_{0}^{2}=k x_{0}^{2}+(3 m) \frac{v_{0}^{2}}{g}$

$\Rightarrow k x_{0}^{2}=m v_{0}^{2}-\frac{m v_{0}^{2}}{3}$

$\Rightarrow k x_{0}^{2}=\frac{2 m v_{0}^{2}}{3}$

$	herefore k=\frac{2 m v_{0}^{2}}{3 x_{0}^{2}}$

A block $C$ of mass $m$ is moving with velocity $v_0$ and collides elastically with block $A$ of mass $m$ which connected to another block $B$ of mass $2\,m$ through a spring of spring constant $k$. What is $k$ if $x_0$ is the compression of spring when velocity of $A$ and $B$ is same?

Similar Questions

Two springs have their force constant as ${k_1}$ and ${k_2}({k_1} > {k_2})$. When they are stretched by the same force

In the diagram shown, no friction at any contact surface. Initially, the spring has no deformation. What will be the maximum deformation in the spring? Consider all the strings to be sufficiency large. Consider the spring constant to be $K$.