Gujarati
Hindi
4-2.Friction
medium

A block of mass $10\, kg$ moving at $10\,m/s$ is released to slide on rough surface having  coefficient of friction $0.2.$ It will stop by travelling distance ........ $m$

A$20$
B$25$
C$30$
D$35$

Solution

$S=\frac{V^{2}}{2 \mu g}=\frac{10^{2}}{2 \times 0.2 \times 10}=25 \mathrm{m}$
Standard 11
Physics

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