2.Motion in Straight Line
hard

A body freely falling from the rest has a velocity $‘v’$ after it falls through a height $‘h’$. The distance it has to fall down for its velocity to become double, is

A

$2h$

B

$4h$

C

$6h$

D

$8h$

Solution

(b) Let at point $A$ initial velocity of body is equal to zero

for path $AB$ : ${v^2} = 0 + 2gh$…(i)

for path $AC $ : ${(2v)^2} = 0 + 2gx$

$4{v^2} = 2gx$…(ii)

Solving (i) and (ii)

$x = 4h$

Standard 11
Physics

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