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2.Motion in Straight Line
hard
A body freely falling from the rest has a velocity $‘v’$ after it falls through a height $‘h’$. The distance it has to fall down for its velocity to become double, is
A
$2h$
B
$4h$
C
$6h$
D
$8h$
Solution

(b) Let at point $A$ initial velocity of body is equal to zero
for path $AB$ : ${v^2} = 0 + 2gh$…(i)
for path $AC $ : ${(2v)^2} = 0 + 2gx$
$4{v^2} = 2gx$…(ii)
Solving (i) and (ii)
$x = 4h$
Standard 11
Physics