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2.Motion in Straight Line
hard
A body is projected with a velocity $u$. It passes through a certain point above the ground after $t_1$ second. The time interval after which the body passes through the same point during the return journey is
A
$\left(\frac{u}{g}-t_1^2\right)$
B
$2\left(\frac{u}{g}-t_1\right)$
C
$\left(\frac{u}{g}-t_1\right)$
D
$\left(\frac{u^2}{g^2}-t_1\right)$
Solution

(b)
Velocity of particle of this instant will be $v=\left(u-g t_1\right)$
Now, the desired time interval will be $\frac{2 v}{g}$ or
$\frac{2\left(u-g t_1\right)}{g}=2\left(\frac{u}{g}-t_1\right)$
Standard 11
Physics