A body is released from top of a tower of height H, metre . After 2, seconds it is stopped and then

English

Gujarati

Hindi

2.Motion in Straight Line

medium

A body is released from the top of a tower of height $H\, metre$. After $2\, seconds$ it is stopped and then instantaneously released. What will be its height after next $2\, seconds$ ?

A

$(H -5)\, metre$

B

$(H -10)\, metre$

C

$(H -20)\, metre$

D

$(H -40)\, metre$

Solution

Distance covered by by the object in first $2 s$ $h_{1}=\frac{1}{2} g t^{2}=\frac{1}{2} \times 10 \times 2^{2}=20 m$

Similarly, destance covered by the object invext $2 s$ will also be $20 m$ hence the required height $=H-20-20=H-40 m$

Standard 11

Physics

Share

Similar Questions

A parachutist after bailing out falls $50\, m$ without friction. When parachute opens, it decelerates at $2\, m/s^2$. He reaches the ground with a speed of $3\, m/s$. At what height, did he bail out ?……..$m$

hard

(AIIMS-2008)

If a ball is thrown at a velocity of $45 \,m / s$ in vertical upward direction, then what would be the velocity profile as function of height? (Assume, $g=10 \,m / s ^2$ )

medium

(KVPY-2018)

A body is projected vertically upward direction from the surface of earth. If upward direction is taken as positive, then acceleration of body during its upward and downyard jourhey are respectively

easy

When a ball is thrown up vertically with velocity ${V_o}$, it reaches a maximum height of '$h$'. If one wishes to triple the maximum height then the ball should be thrown with velocity

medium

(AIIMS-2005)

A body falling under gravity covers two points ${A}$ and ${B}$ separated by $80\ m$ in $2 \ s$. The distance of upper point $A$ from the starting point is ${m}$ (use ${g}=10 \ m s^{-2}$).

hard

(JEE MAIN-2024)