A body of mass 1, kg lies on smooth inclined plane. body is given force F = 10N horizont

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4-1.Newton's Laws of Motion

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A body of mass $1\, kg$ lies on smooth inclined plane. The body is given force $F = 10N$ horizontally as shown. The magnitude of net normal reaction on the body is

A$10 \sqrt 2 \,N$

B$\frac{10}{\sqrt 2} \,N$

C$10\,N$

DNone of these

Solution

$\mathrm{N}=\mathrm{F} \sin 45^{\circ}+\mathrm{mg} \cos 45^{\circ}=\frac{10}{\sqrt{2}}+\frac{10}{\sqrt{2}}=10 \sqrt{2}$

Standard 11

Physics

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