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4-1.Newton's Laws of Motion
easy
A body of mass $2 \,kg $ collides with a wall with speed $100\, m/s$ and rebounds with same speed. If the time of contact was $1/50 \,second$, the force exerted on the wall is
A
$8 \,N$
B
$2 \times {10^4}\,N$
C
$4\, N$
D
${10^4}\,N$
Solution
(b)$F = \frac{{dp}}{{dt}} = m\frac{{dv}}{{dt}} = \frac{{m \times 2v}}{{1/50}}$= $\frac{{2 \times 2 \times 100}}{{1/50}} = 2 \times {10^4}N$
Standard 11
Physics
