A body of mass 5 ,kg is moving with velocity of vec{v}=(2 i+6 hat{j}) ,m / s at t=0 ,s . After time

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4-1.Newton's Laws of Motion

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A body of mass $5 \,kg$ is moving with velocity of $\vec{v}=(2 i+6 \hat{j}) \,m / s$ at $t=0 \,s$. After time $t =2 \,s$, velocity of body is $(10 \hat{i}+6 \hat{j})$, then change in momentum of body is ......... $kg m / s$

A

$40 \hat{i}$

B

$20 \hat{i}$

C

$30 \hat{i}$

D

$(50 i+30 \hat{j})$

Solution

(a)

Given,

Initial velocity $\overrightarrow{ V }_{\text {intital }}=\left(2_1^{\hat{1}}+6 \hat{ f }\right) m / s$

Final velocity $\vec{V}_{\text {final }}=(10 \hat{i}+6 \hat{j}) m / s$

Change in momentum $\triangle P$

$\Delta P =\text { Mass } \times\left(\overrightarrow{ V }_{\text {final }}-\overrightarrow{ V }_{\text {initial }}\right)$

$\Delta P =5 \times[(10 \hat{ i }+6 \hat{ j })-(2 \hat{1}+6 \hat{ j })]$

$\Delta P =40 \hat{ i } kg ms ^{-1}$

Change in momentum $40\,i\, kg m / s$

Standard 11

Physics

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