A body of weight 200 mathrm{~N} is suspended form a tree branch thought a chain of mass 10 mathrm{~k

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4-1.Newton's Laws of Motion

hard

A body of weight $200 \mathrm{~N}$ is suspended form a tree branch thought a chain of mass $10 \mathrm{~kg}$. The branch pulls the chain by a force equal to (if $g=10 \mathrm{~m} / \mathrm{s}^2$ ):

A

$150 \mathrm{~N}$

B

$300 \mathrm{~N}$

C

$200 \mathrm{~N}$

D

$100 \mathrm{~N}$

(JEE MAIN-2024)

Solution

Chain block system is in equilibrium so

$\mathrm{T}=200+100=300 \mathrm{~N} \text {. }$

Standard 11

Physics

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