A body of weight 50 ,N placed on a horizontal | vedclass

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Question

(b) Frictional force = $f = 28.2\cos 45^\circ $ $ = 28.2 	imes \frac{1}{{\sqrt 2 }} = 20\;N$

Normal reaction $R = 50 - 28.2\sin 45^\circ $$ = 30\;

Vedclass · Accepted Answer

$20\, N, 30\, N$

Vedclass · Answer

(b) Frictional force = $f = 28.2\cos 45^\circ $ $ = 28.2 	imes \frac{1}{{\sqrt 2 }} = 20\;N$

Normal reaction $R = 50 - 28.2\sin 45^\circ $$ = 30\;N$

A body of weight $50 \,N$ placed on a horizontal surface is just moved by a force of $28.2\, N$. The frictional force and the normal reaction are

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