A body starts from rest with uniform acceleration $a,$ its velocity after $n\,seconds$ is $v$. The displacement of the body in last $3\,s$ is : (assume total time of journey from $0$ to $n\,seconds$ )
$\frac{{v(6n - 9)}}{{2n}}$
$\frac{2{v(6n - 9)}}{{n}}$
$\frac{2{v(2n + 1)}}{{n}}$
$\frac{2{v(n - 1)}}{{n}}$
A bullet fired into a fixed target loses half of its velocity after penetrating $3\,cm$ . How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion?.......$cm$
What is the relation between displacement, time and acceleration in case of a body having uniform acceleration
A bullet fired into a fixed target loses half of its velocity after penetrating $3\,cm$. How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion?........$cm$
The velocity $v$ of a particle moving along $x$-axis varies with its position $(x)$ as $v=\alpha \sqrt{x}$; where $\alpha$ is a constant. Which of the following graph represents the variation of its acceleration (a) with time $(t)$ ?