A body travels for $15\, sec$ starting from rest with constant acceleration. If it travels distances ${S_1},\;{S_2}$ and ${S_3}$ in the first five seconds, second five seconds and next five seconds respectively the relation between ${S_1},\;{S_2}$ and ${S_3}$ is
${S_1} = {S_2} = {S_3}$
$5{S_1} = 3{S_2} = {S_3}$
${S_1} = \frac{1}{3}{S_2} = \frac{1}{5}{S_3}$
${S_1} = \frac{1}{5}{S_2} = \frac{1}{3}{S_3}$
If average velocity of particle moving on a straight line is zero in a time interval, then
If a freely falling body travels in the last second a distance equal to the distance travelled by it in the first three second, the time of the travel is........$sec$
The ratio of displacement in $n$ second and in the $n^{th}$ second for a particle moving in a straight line under constant acceleration starting from rest is
A body falls from a large height. The ratio of distance traveled in each time interval $t_0$ during $t = 0$ to $t = 3\, t_0$ of the journey is
The motion of a particle along a straight line is described by equation $x = 8 + 12t -t^3$ where $x$ is in metre and $t$ in second. The retardation of the particle when its velocity becomes zero is.......$ms^{-2}$