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7.Alternating Current
hard
A bulb and a capacitor are connected in series across an ac supply. A dielectric is then placed between the plates of the capacitor. The glow of the bulb:
A
increases
B
remains same
C
becomes zero
D
decreases
(JEE MAIN-2024)
Solution

$\mathrm{Z}=\sqrt{\mathrm{R}^2+\mathrm{X}_{\mathrm{C}}^2} \& \mathrm{X}_{\mathrm{C}}=\frac{1}{\mathrm{WC}}$
due to dielectric
$\mathrm{C} \uparrow \Rightarrow \mathrm{X}_{\mathrm{c}} \downarrow \Rightarrow \mathrm{Z} \downarrow$
So, current increases & thus bulb will glow more brighter.
Standard 12
Physics
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