A calorimeter contains 0.2, kg of water at 30,^oC , 0.1,kg of water at 60,^oC is added to it, mixtur

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10-1.Thermometry, Thermal Expansion and Calorimetry

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A calorimeter contains $0.2\, kg$ of water at $30\,^oC$, $0.1\,kg$ of water at $60\,^oC$ is added to it, the mixture is well stirred and the resulting temperature is found to be $35\,^oC$. The thermal capacity of calorimeter is .......... $J/K$

A

$6300$

B

$1260$

C

$4200$

D

$8400$

Solution

Heat gained by

Calorimeter $=[\mathrm{x} \times(35-30)]$

By water (Heat gain) $\Rightarrow 0.2 \times 4.2 \times 10^{3} \times(35-30)$

Heat Loss by water $=0.1 \times 4.2 \times 10^{3} \times(60-35)$

Total Heat lost $=$ Total heat gain

$0.1 \times 4.2 \times 10^{3} \times(60-35)$

$=0.2 \times 4.2 \times 10^{3} \times(35-30)+\mathrm{x}(35-30)$

$(x=1260 \mathrm{J} / \mathrm{k})$

Standard 11

Physics

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