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A car is moving along a straight line, say $OP$ in given figure. It moves from $O$ to $P$ in $18\; s$ and returns from $P$ to $\mathrm{Q}$ in $6.0\; s$. What are the average velocity and average speed of the car in going from $O$ to $P$?
$20 \;\mathrm{m} \mathrm{s}^{-1}\;,\;20 \;\mathrm{m} \mathrm{s}^{-1}$
$20 \;\mathrm{m} \mathrm{s}^{-1}\;,\;30 \;\mathrm{m} \mathrm{s}^{-1}$
$10 \;\mathrm{m} \mathrm{s}^{-1}\;,\;20 \;\mathrm{m} \mathrm{s}^{-1}$
$20 \;\mathrm{m} \mathrm{s}^{-1}\;,\;10 \;\mathrm{m} \mathrm{s}^{-1}$
Solution
Average velocity $=\frac{\text { Displacement }}{\text { Ttme tnterval }}$
$\bar{v}=\frac{+360 \mathrm{m}}{18 \mathrm{s}}=+20 \mathrm{m} \mathrm{s}^{-1}$
$\text {Average speed }=\frac{\text { Path length }}{\text { Tune truterval }}$
$=\frac{360 \mathrm{m}}{18 \mathrm{s}}=20 \mathrm{m} \mathrm{s}^{-1}$
