A car is moving at a speed of 40,m/s on a circular track of radius 400,m. This speed is increasing a

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3-2.Motion in Plane

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A car is moving at a speed of $40\,m/s$ on a circular track of radius $400\,m.$ This speed is increasing at the rate of $3\,m/s^2.$ The acceleration of car is ........ $m/s^2$

A$4$

B$7$

C$5$

D$3$

Solution

$a_{t}=3 \mathrm{m} / \mathrm{s}^{2}$
$a_{c}=\frac{v^{2}}{r}=\frac{1600}{400}=4$
$a=\sqrt{a_{c}^{2}+a_{t}^{2}}=5 \mathrm{m} / \mathrm{s}^{2}$

Standard 11

Physics

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