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1. Electric Charges and Fields
medium
A charge $Q$ is uniformly distributed over a large square plate of copper. The electric field at a point very close to the centre of the plane is $10\, V/m$. If the copper plate is replaced by a plastic plate of the same geometrical dimensions and carrying the same charge $Q$ uniformly distributed, then the electric field at the point $P$ will be......$V/m$
A
$5 $
B
$0$
C
$10$
D
$20$
Solution
Electric field will remain same
in case of copper plate $\sigma=\frac{Q}{2 \mathrm{A}}$
$\therefore $ $\mathrm{E}=\frac{\sigma}{\epsilon_{0}}=\frac{\mathrm{Q}}{2 \mathrm{A} \in_{0}}$
in case of plastic plate $\sigma=\frac{Q}{A}$
$\therefore $ $\mathrm{E}=\frac{\sigma}{2 \mathrm{e}_{0}}=\frac{\mathrm{Q}}{2 \mathrm{A} \in_{0}}$
Standard 12
Physics