A circular disc of radius $R$ has a uniform thickness. A circular hole of diameter equal  to the radius of disc has been cut out as shown. Distance of centre of mass of the  remaining disc from point $O$ is

830-5

  • A

    $\frac{R}{14}$

  • B

    $\frac{R}{12}$

  • C

    $\frac{R}{8}$

  • D

    $\frac{R}{6}$

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