A clock has a continuously moving second's hand of 0.1, m length. average acceleration of tip of

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3-2.Motion in Plane

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A clock has a continuously moving second's hand of $0.1\, m$ length. The average acceleration of the tip of the hand (in units of $ms ^{-2}$ ) is of the order of

A

$10^{-3}$

B

$10^{-2}$

C

$10^{-4}$

D

$10^{-1}$

(JEE MAIN-2020)

Solution

$R=0.1 m$

$\omega=\frac{2 \pi}{ T }=\frac{2 \pi}{60}=0.105 rad / sec$

$a =\omega^{2} R$

$=(0.105)^{2}(0.1)$

$=0.0011$

$=1.1 \times 10^{-3}$

Average acceleration is of the order of $10^{-3}$

Standard 11

Physics

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