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7.Alternating Current
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A coil, a capacitor and an $AC$ source of $rms$ voltage $24 \,V$ are connected in series. By varying the frequency of the source, a maximum $rms$ current of $6\,A$ is observed. If coil is connected to a battery of $emf$ $12 \,volt$ and internal resistance $4\,\Omega$, then current through it in steady state is......$A$
A
$2.4 $
B
$1.8 $
C
$1.5 $
D
$1.2$
Solution
$\mathrm{E}_{\mathrm{rms}}=24 \mathrm{V}$
$r=4 \Omega, 1_{\mathrm{rms}}=6 \mathrm{A}$
$\mathrm{R}=\mathrm{E} / \mathrm{I}=24 / 6=4 \Omega$
Internal Resistance $=4 \Omega$
Hence net resistance $=4+4=8 \Omega$
$\therefore$ Current $=12 / 8=1.5 \mathrm{A}$
Standard 12
Physics
