A coil of inductance 0.20, H is connected in series with a switch and a cell of emf 1.6, V . total r

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7.Alternating Current

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A coil of inductance $0.20\, H$ is connected in series with a switch and a cell of $emf$ $1.6\, V$. The total resistance of the circuit is $4.0\, \Omega $. What is the initial rate of growth of the current when the switch is closed ?.......$A\, s^{-1}$

A

$0.050$

B

$0.40$

C

$0.13$

D

$8$

Solution

$\mathrm{V}=\mathrm{Rl}+\mathrm{L} \frac{\mathrm{dl}}{\mathrm{dt}},$ at $\mathrm{t}=0, \mathrm{I}=0,$ thus we have

$\frac{\mathrm{d} l}{\mathrm{dt}}=\frac{\mathrm{V}}{\mathrm{L}}=\frac{1.6}{0.2}=8 \mathrm{\,A} / \mathrm{s}$

Standard 12

Physics

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