A constant force acting on a body of mass of 5,kg changes its speed from 5,ms^{-1} to 10,ms^{-1} in

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4-1.Newton's Laws of Motion

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A constant force acting on a body of mass of $5\,kg$ changes its speed from $5\,ms^{-1}$ to $10\,ms^{-1}$ in $10\,s$ without changing the direction of motion. The force acting on the body is ......... $N$

A

$1.5$

B

$2$

C

$2.5$

D

$5$

Solution

$a=\frac{v-u}{t}=\frac{(10-5) m s^{-1}}{10 s}=0.5 \mathrm{ms}^{-2}$

As $\mathrm{F}=\mathrm{ma}$

$\therefore \mathrm{F}=(5 \mathrm{kg})\left(0.5 \mathrm{ms}^{-2}\right)=2.5 \mathrm{N}$

Standard 11

Physics

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