A cube of edge length 10 ,cm is just balanced at interface of two liquids A and B as shown in figure

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9-1.Fluid Mechanics

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A cube of edge length $10 \,cm$ is just balanced at the interface of two liquids $A$ and $B$ as shown in figure. If $A$ and $B$ has specific gravity $0.6$ and $0.4$ respectively, then mass of cube is ................ $g$

A

$240$

B

$360$

C

$480$

D

$540$

Solution

(c)

$m g=F B$ (Buoyant face)

$m g=\left(v_1 \rho_1 g\right)+\left(v_2 \rho_2 g\right)$

$m=\left(v_1 \rho_1+v_2 \rho_2\right) \quad \rho_1=600\,kg / m ^3$

$=480 \times 10^3 \times 10^{-6}\,Kg$

$1\,m =480\,gm$

Standard 11

Physics

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