A cylindrical metallic rod in thermal contact with two reservoirs of heat at its two ends conducts a

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10-2.Transmission of Heat

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A cylindrical metallic rod in thermal contact with two reservoirs of heat at its two ends conducts an amount of heat $Q$ in time $t$. The metallic rod is melted and the material is formed into a rod of half the radius of the original rod. What is the amount of heat conducted by the new rod, when placed in thermal contact with same two reservoirs in time $t$

A

$\frac{Q}{2}$

B

$\frac{Q}{4}$

C

$\frac{Q}{16}$

D

$2Q$

Solution

$\quad \frac{{\rm{Q}}}{{\rm{t}}} = \frac{{{\rm{kA}}\left( {{{\rm{T}}_1} – {{\rm{T}}_2}} \right)}}{l}$

$\frac{{{{\rm{Q}}^\prime }}}{{\rm{t}}} = \frac{{{\rm{k}}\left( {\frac{{\rm{A}}}{4}} \right)\left( {{{\rm{T}}_1} – {{\rm{T}}_2}} \right)}}{{4l}}$

$ = \frac{1}{{16}}\frac{{{\rm{kA}}\left( {{{\rm{T}}_1} – {{\rm{T}}_2}} \right)}}{l}$

$ \Rightarrow {{\rm{Q}}^\prime } = \frac{{\rm{Q}}}{{16}}$

Standard 11

Physics

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