4-1.Newton's Laws of Motion
easy

A force of $50$ dynes is acted on a body of mass $5$ g which is at rest for an interval of $3$ seconds, then impulse is

A$0.15 \times {10^{ - 3}}\,N{\rm{ - }}s$
B$0.98 \times {10^{ - 3}}\,N{\rm{ - }}s$
C$1.5 \times {10^{ - 3}}\,N{\rm{ - }}s$
D$2.5 \times {10^{ - 3}}\,N{\rm{ - }}s$

Solution

(c) Impulse = Force $×$ Time $= 50 × 10^{-5} × 3$
$= 1.5 × 10^{-3}\ N-s$
Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.