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11.Thermodynamics
easy
A gas undergoes a change of state during which $100 J$ of heat is supplied to it and it does $20 J$ of work. The system is brought back to its original state through a process during which $20 J$ of heat is released by the gas. The work done by the gas in the second process is ....... $J$
A
$60 $
B
$40 $
C
$80 $
D
$20 $
Solution
(a) In a cyclic process $\Delta U = 0$==> $\Delta Q = \Delta W$
==> $(100 – 20) = 20 + {W_2}$ ==> ${W_2} = 60\,J$
Standard 11
Physics
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