Gujarati
Hindi
12.Kinetic Theory of Gases
normal

A gaseous mixture consists of $16\  g$ of helium and $16\  g$ of oxygen. The ratio $\frac{{{C_p}}}{{{C_v}}}$ of the mixture is

A

$1.59$

B

$1.62$

C

$1.4$

D

$1.54$

Solution

For mixture of gases, $C_{v}=\frac{n_{1} C_{v_{1}}+n_{2} C_{v_{2}}}{n_{1}+n_{2}}$

Twhere $C=\frac{f}{2} R, f$ is degree of freedom and $C_{p}=\frac{n_{1} C_{P_{1}}+n_{2} C_{R_{3}}}{n_{1}+n_{2}}$

where $C_{p}=\left(1+\frac{f}{2}\right) R$

For helium, $n_{1}=4, f=3$

For oxygen, $n_{2}=\frac{1}{2}, f=5$

$\therefore \frac{C_{p}}{C_{v}}=\frac{4 \times \frac{5 R}{2}+\frac{1}{2} \times \frac{7 R}{2}}{4 \times \frac{3 R}{2}+\frac{1}{2} \times \frac{5 R}{2}}=\frac{47}{29}$

$=1.62$

Standard 11
Physics

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