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4.Principles of Inheritance and Variation
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A girl of normal vision whose father was colourblind marries a man of normal vision whose father was also colourblind. Their sons would be (of total number of $sons$)
A
All colourblind
B
$50\%$ colourblind
C
All normal
D
$25\%$ colourblind
Solution
(b) Infact the girl with normal vision is carrier because her father is colourblind (daughter of colourblind father are either colourblind or carrier) and when she marries a normal man the possibility of their sons being colourblind is $50\%$ because the genotype of parents is $X^CX$ and $XY$,
so only half of the possible combinations of $XY$ have the $X$-linked recessive genes which exhibit the disease.
Standard 12
Biology
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