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10-1.Thermometry, Thermal Expansion and Calorimetry
medium
A glass flask contains some mercury at room temperature. It is found that at different temperatures the volume of air inside the flask remains the same. If the volume of mercury in the flask is $300 \,\,cm^3$, then volume of the flask is ........ $cm^3$. (given that coefficient of volume expansion of mercury and coefficient of linear expansion of glass are $1.8 × 10^{-4} (^o C)^{-1}$ and $9 × 10^{-6} (^o C)^{-1}$ respectively)
A
$4500$
B
$450$
C
$2000$
D
$6000$
Solution
since the volume of air inside the flask remains same,
$\gamma_{\text {mercury}} V_{\text {mercury}}=\gamma_{\text {flask}} V_{\text {flask}}$
$\Rightarrow 1.8 \times 10^{-4} \times 300=3 \times\left(9 \times 10^{-6}\right) V_{f l a s k}$
$V_{\text {flask}}=2000 \mathrm{cc}$
Standard 11
Physics
