- Home
- Standard 11
- Physics
10-1.Thermometry, Thermal Expansion and Calorimetry
medium
A hammer of mass $1kg$ having speed of $50 \,m/s$, hit a iron nail of mass $200\, gm.$ If specific heat of iron is $0.105\, cal/gm°C$ and half the energy is converted into heat, the raise in temperature of nail is........ $^oC$
A
$7.1$
B
$9.2$
C
$10.5$
D
$12.1$
Solution
(a) $W = JQ$ $\Rightarrow$ $\frac{1}{2}\left( {\frac{1}{2}M{v^2}} \right) = J(m.c.\Delta \theta )$
$\Rightarrow$ $\frac{1}{4} \times 1 \times {(50)^2} = 4.2[200 \times 0.105 \times \Delta \theta ]$$\Rightarrow$ $\Delta \theta = 7.1^\circ C$
Standard 11
Physics
