A man is, d distance behind a bus. The bus mo | vedclass

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Question

(c)

Let us see the relative motion, distance moved by the man before coming to rest

$0=v^2-2 a s 	ext { or } s=\frac{v^2}{2 a}$

Now, man can

Vedclass · Accepted Answer

$(a)$ and $(c)$ Only

Vedclass · Answer

(c)

Let us see the relative motion, distance moved by the man before coming to rest

$0=v^2-2 a s 	ext { or } s=\frac{v^2}{2 a}$

Now, man can catch the bus if,

$s \geq d 	ext { or } v \geq \sqrt{2 a d}$

If he just catches the bus, then

$0 =v-a t$

$t =\frac{v}{a}$

A man is, $d$ distance behind a bus. The bus moves away from the man with an acceleration $a$. At the same time, man starts running towards bus with a constant velocity $v$.

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