A man of blood group- A , marries a woman of blood group- B , both of them are heterozygous for bloo

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4.Principles of Inheritance and Variation

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A man of blood group-$A$, marries a woman of blood group-$B$, both of them are heterozygous for blood group, chances of their first child having blood group $AB$ will be

A

$25\, \%$

B

$50\, \%$

C

$75 \,\%$

D

$100\, \%$

Solution

There is $25\, \%$ chances of first offspring having blood group-$AB.$

Standard 12

Biology

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