Gujarati
Hindi
9-1.Fluid Mechanics
normal

A manometer reads the pressure of a gas in an enclosure as shown in the figure.

The absolute and gauge pressure of the gas in $cm$ of mercury is
(Take atmospheric pressure $= 76\,cm$ of mercury)

A

$76,\, 20$

B

$20,\, 76$

C

$96,\,20$

D

$20,\, 96$

Solution

Atmospheric pressure, $P_{0}=76 \mathrm{cm}$ of $\mathrm{Hg}$

Difference between the levels of mercury in the two limbs gives gauge pressure

Hence, gauge pressure is $20 \mathrm{cm}$ of $\mathrm{Hg}$

Absolute pressure $=$ Atmospheric pressure $+$ Gauge pressure

$=76+20=96 \mathrm{cm}$ of $\mathrm{Hg}$

Standard 11
Physics

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