A mass is performing vertical circular motion (see figure). If average velocity of particle is incre

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5.Work, Energy, Power and Collision

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A mass is performing vertical circular motion (see figure). If The average velocity of the particle is increased, then at which point the string will break

$A$

$B$

$C$

$D$

(AIPMT-2000)

Solution

Tension at any point in vertical motion is given by :

$T =\frac{ mv ^{2}}{ l }+ mg \cos \theta$

$\theta=$ angular displacement from lowest point,

$l=$ length of string

$m =$ mass of string

It is clear that tension at the lowest point $(B)$ is greatest than at other points ($A, C , D$ ). If we increase average velocity, tension will increase at lowest point, therefore at point B, string has maximum possibility of break.

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A mass is performing vertical circular motion (see figure). If The average velocity of the particle is increased, then at which point the string will break

Solution

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