Gujarati
Hindi
3.Current Electricity
hard

A meter bridge is set-up as shown, to determine an unknown resistance ' $X$ ' using a standard $10$ ohm resistor. The galvanometer shows null point when tapping-key is at $52 \ cm$ mark. The end-corrections are $1 \ cm$ and $2 \ cm$ respectively for the ends $A$ and $B$. The determined value of ' $X$ ' is

A

$10.2 \ ohm$

B

$10.6 \ ohm$

C

$10.8 \ ohm$

D

$11.1 \ ohm$

(IIT-2011)

Solution

Using the condition for balanced Wheatstone bridge, we get

$\frac{X}{10}=\frac{(52+1) cm }{(100-52+2) cm }=\frac{53}{50}$

or $X=\frac{53 \times 10}{50}=10.6 \ \Omega$

Standard 12
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.