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Question

Fractional decrease in kinetic energy of neutron

$=1-\left(\frac{m_{1}-m_{2}}{m_{1}+m_{2}}ight)^{2} \quad\left(	ext { As } m_{1}=1 	ext { and }

Vedclass · Accepted Answer

$8/9$

Vedclass · Answer

Fractional decrease in kinetic energy of neutron

$=1-\left(\frac{m_{1}-m_{2}}{m_{1}+m_{2}}ight)^{2} \quad\left(	ext { As } m_{1}=1 	ext { and } m_{2}=2ight)$

$=1-\left(\frac{1-2}{1+2}ight)^{2}=1-\left(\frac{1}{3}ight)^{2}=1-\frac{1}{9}=\frac{8}{9}$

A neutron makes a head-on elastic collision with a stationary deuteron. The fractional energy loss of the neutron in the collision is

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