Gujarati
Hindi
5.Work, Energy, Power and Collision
normal

A neutron makes a head-on elastic collision with a stationary deuteron. The fractional energy loss of the neutron in the collision is

A

$16/81$

B

$8/9$

C

$8/27$

D

$2/3$

Solution

Fractional decrease in kinetic energy of neutron

$=1-\left(\frac{m_{1}-m_{2}}{m_{1}+m_{2}}\right)^{2} \quad\left(\text { As } m_{1}=1 \text { and } m_{2}=2\right)$

$=1-\left(\frac{1-2}{1+2}\right)^{2}=1-\left(\frac{1}{3}\right)^{2}=1-\frac{1}{9}=\frac{8}{9}$

Standard 11
Physics

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