A nucleus at rest splits into two nuclear par | vedclass

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Question

$\frac{\mathrm{r}_{1}}{\mathrm{r}_{2}}=\frac{1}{2} \mathrm{so} \frac{\mathrm{m}_{1}}{\mathrm{m}_{2}}=\frac{\frac{4}{3} \pi \mathrm{r}_{1}^{3}}{\frac{4

Vedclass · Accepted Answer

$8 : 1$

Vedclass · Answer

$\frac{\mathrm{r}_{1}}{\mathrm{r}_{2}}=\frac{1}{2} \mathrm{so} \frac{\mathrm{m}_{1}}{\mathrm{m}_{2}}=\frac{\frac{4}{3} \pi \mathrm{r}_{1}^{3}}{\frac{4}{3} \pi \mathrm{r}_{2}^{3}} \frac{ho}{ho}=\frac{\mathrm{r}_{1}^{3}}{\mathrm{r}_{2}^{3}}=\frac{1}{8}$

$\mathrm{m}_{1}=\mathrm{m}_{0}, \quad \mathrm{m}_{2}=8 \mathrm{m}_{0}$

as $\mathrm{M} 	imes 0=\mathrm{m}_{1} \mathrm{v}_{1}+\mathrm{m}_{2} \mathrm{v}_{2}$

$\mathrm{m}_{1} \mathrm{v}_{1}=-\mathrm{m}_{2} \mathrm{v}_{2}$

$\left|\frac{v_{1}}{v_{2}}ight|=\frac{m_{2}}{m_{1}}=\frac{8}{1}$

A nucleus at rest splits into two nuclear parts having same density and the radii in the ratio $1 : 2$ . Their velocities are in ratio ———

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