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4.Average
medium
A number, $x,$ equals $80 \%$ of the average of $5,7,$ $14$ and a number $y$. If the average of $x$ and $y$ is $26$ then value of $y$ is
A
$13$
B
$26$
C
$39$
D
$52$
Solution
Average of $5,7,14$ and $y=\frac{5+7+14+y}{4}$
Therefore, $x=80 \%$ of $\frac{5+7+14+y}{4}=\frac{80}{100} \times \frac{26+y}{4}$
$\Rightarrow x=\frac{26+y}{5}$…..$(1)$
Also $\frac{x+y}{2}=26$…..$(2)$
From,
$(1)$ and $(2),$ we get $52-y=\frac{26+y}{5} \Rightarrow y=39$
Standard 13
Quantitative Aptitude
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