A number, x, equals 80 % of average of 5,7, 14 and a number y . If average of x and y is 26 then val

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4.Average

medium

A number, $x,$ equals $80 \%$ of the average of $5,7,$ $14$ and a number $y$. If the average of $x$ and $y$ is $26$ then value of $y$ is

A

$13$

B

$26$

C

$39$

D

$52$

Solution

Average of $5,7,14$ and $y=\frac{5+7+14+y}{4}$

Therefore, $x=80 \%$ of $\frac{5+7+14+y}{4}=\frac{80}{100} \times \frac{26+y}{4}$

$\Rightarrow x=\frac{26+y}{5}$…..$(1)$

Also $\frac{x+y}{2}=26$…..$(2)$

From,

$(1)$ and $(2),$ we get $52-y=\frac{26+y}{5} \Rightarrow y=39$

Standard 13

Quantitative Aptitude

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