Gujarati
Hindi
1. Electric Charges and Fields
normal

A parallel plate capacitor is charged to a potential difference of $100\,V$ and disconnected from the source of $emf$. A slab of dielectric is then inserted between the plates. Which of the following three quantities change?

$(i)$ The potential difference    $(ii)$ The capacitance    $(iii)$ The charge on the plates

A

only $(i)$ and $(ii)$

B

only $(i)$ and $(iii)$

C

only $(ii)$ and $(iii)$

D

All $(i),\, (ii)$ and $(iii)$

Solution

The charge of the plates cannot change because the plates are isolated. Inserting the dielectric changes the capacitance and therefore changes the potential difference (from $\mathrm{V}=\mathrm{Q} / \mathrm{C}$ ), since the charge is fixed.

Standard 12
Physics

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